Question #47e74

1 Answer
anor277 · Solace M.
Sep 25, 2017

#Ni(ClO_4)_2(s)stackrel(H_2O)rarrNi^(2+) + 2ClO_4^(-)#

Explanation:

As with any chemical reaction, MASS and CHARGE are conserved absolutely. We started with a NEUTRAL material, and the TOTAL charge of the ions on the right hand side is neutral. We started with approx. #258*g# of the perchlorate. There are precisely #258.8*g# in solution.

Therefore we started with 4 moles of #Ni(ClO_4)_2#. I think that when this dissolves in solution, there will be FOUR MOLES of #Ni^(2+)#, and HOW MANY MOLES of perchlorate anion?

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