How do you solve $- 2 < (2 - 2 x) < 3$ $-2< ( 2- 2x ) < 3$ ?

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How do you solve $- 2 < (2 - 2 x) < 3$ $-2< ( 2- 2x ) < 3$ ?

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Answer 1 · 2017-09-27T14:48:55

$- \frac{1}{2} < x < 2$ $- frac{1}{2} < x < 2$

Explanation:

$- 2 < (2 - 2 x) < 3$ $-2<(2-2x)<3$
$- 4 < - 2 x < 1$ $-4<-2x<1$
$2 > x > - \frac{1}{2}$ $2>x> -frac{1}{2}$
Therefore:
$- \frac{1}{2} < x < 2$ $- frac{1}{2} < x < 2$

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How do you solve $- 2 < (2 - 2 x) < 3$ $-2< ( 2- 2x ) < 3$ ?

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Science

Math

Humanities

... and beyond

How do you solve −2<(2−2x)<3-2< ( 2- 2x ) < 3?

1 Answer

Explanation:

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How do you solve $- 2 < (2 - 2 x) < 3$ $-2< ( 2- 2x ) < 3$ ?