How do you simplify $- (3 - \frac{21}{6}) - \frac{1}{3} < 0$ $-( 3- \frac { 21} { 6} ) - \frac { 1} { 3} < 0$ ?

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Answer 1 · 2017-09-28T05:51:20

straight math, but sadly the statement isn't true

apply your bedmas, eliminate the fractions and solve

$- (3 - \frac{21}{6}) - \frac{1}{3} < 0$ $-(3 - 21/6) - 1/3 < 0$

$- 3 + \frac{21}{6} - \frac{1}{3} < 0$ $-3 + 21/6 - 1/3 < 0$

$- 18 + 21 - 2 < 0$ $-18 + 21 - 2 < 0$

$1 < 0$ $1 < 0$

no it isn't

How do you simplify -( 3- \frac { 21} { 6} ) - \frac { 1} { 3} < 0−(3−216)−13<0-( 3- \frac { 21} { 6} ) - \frac { 1} { 3} < 0?