Question #d0697

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Question #d0697

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Answer 1 · 2017-09-29T10:21:57

65 moles of hydrogen atoms, or more correctly,
$3.91 \cdot 10^{25}$ $3.91 * 10^25$ hydrogen atoms

Explanation:

First we calculate the number of moles of methane,
$n = \frac{w e i g h t}{m o l a r m a s s}$ $n = (weight) / (molar mass)$

$\Rightarrow n = \frac{260}{16} = 16.25$ $implies n = 260/16 = 16.25$ ( molar mass of methane = 16g/mol)

Hence 16.25 moles of methane are present, which implies that number of moles of hydrogen atoms = $(16.25) \cdot (4) = 65$ $(16.25) * (4) = 65$
This is because there are 4 hydrogen atoms in each molecule of methane.

65 moles of hydrigen atoms = $65 \cdot N_{A} = 65 \cdot 6.022 \cdot 10^{23}$ $65 * N_A = 65 * 6.022 * 10^23$

which can be equivalently written as $3.91 \cdot 10^{25}$ $3.91 * 10^25$ hydrogen atoms

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