How do you solve #6( y - 3) = 8y - 30#?

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Answer 1 · 2017-09-29T21:32:00

#y = 6#

expand your brackets, collect like terms and simplify

#6(y- 3) = 8y - 30#
#6y - 18 = 8y - 30#

add 18 to both sides

#6y = 8y - 12#

subtract #8y# from both sides to isolate #y#

#-2y = -12#

divide all by #-2# to solve for #y#

#y = 6#