How do you simplify #(1-2i)(3+4i)#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Pankaj Solanki Oct 1, 2017 #11-2i# Explanation: #(1-2i)(3+4i)# Just Multiply terms #=(1)(3+4i)-2i(3+4i)# #=3+4i-6i-8i^2# Using Property #i=sqrt-1# and #i^2=-1# #=3-2i+8# #=11-2i# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1969 views around the world You can reuse this answer Creative Commons License