How do you write an equation of a line passing through (6, 1), perpendicular to $4 y - 2 = 3 x$ $4y - 2 = 3x$ ?

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How do you write an equation of a line passing through (6, 1), perpendicular to $4 y - 2 = 3 x$ $4y - 2 = 3x$ ?

1 Answer

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Question #3177e
How do you find the equation of the line through the point (-4 , 5) and is perpendicular to the x axis?

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Answer 1 · 2017-10-02T01:56:02

$3 y + 4 x = 27$ $3y+4x=27$

Explanation:

$4 y - 2 = 3 x$ $4y-2=3x$
$4 y = 3 x + 2$ $4y=3x+2$
$y = (\frac{3}{4}) x + (\frac{1}{2})$ $y=(3/4)x+(1/2)$
Slope of the line $m 1 = \frac{3}{4}$ $m1=3/4$
Slope of perpendicular line $m 2 = - \frac{1}{m 1} = - (\frac{1}{\frac{3}{4}}) = - (\frac{4}{3})$ $m2=-1/(m1)=-(1/(3/4))=-(4/3)$
Equation of the perpendicular line
$(y - 1) = - (\frac{4}{3}) (x - 6)$ $(y-1)=-(4/3)(x-6)$
$3 y - 3 = - 4 x + 24$ $3y-3=-4x+24$
$3 y + 4 x = 27$ $3y+4x=27$

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How do you write an equation of a line passing through (6, 1), perpendicular to $4 y - 2 = 3 x$ $4y - 2 = 3x$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you write an equation of a line passing through (6, 1), perpendicular to 4y−2=3x4y - 2 = 3x?

1 Answer

Explanation:

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Impact of this question

How do you write an equation of a line passing through (6, 1), perpendicular to $4 y - 2 = 3 x$ $4y - 2 = 3x$ ?