Question #b83fb

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Answer 1 · 2017-10-05T02:23:26

A) $3.25 xx 10^(-19)J$
B) $5.00 xx 10^14s^(-1)$
C) $612 nm$ (Red light)

A) An $eV = 1.6 xx 10^(-19)J$ ; $8.82 – 6.79 = 2.03eV$ ;
$2.03 xx 1.6 xx 10^(-19)J = 3.25 xx 10^(-19)J$

B) ν = c/λ
Calculate the wavelength required for the specified energy, then calculate the corresponding frequency.

$ν = (3.25 xx 10^(-19))/(6.63 xx 10^(-34) Js)$

$ν = 5.00 xx 10^14s^(-1)$

C) $E_"photon" = (hc)/λ$
where:
$h = 6.63 xx 10^(-34) Js$
$c = 3.0 xx 10^8 m/s$
$λ = m (or nm xx 10^(-9))$

$3.25 xx 10^(-19)J = (6.63 xx 10^(-34) J xx 3.0 xx 10^8)/λ$

$λ = (6.63 xx 10^(-34) J xx 3.0 xx 10^8)/(3.25 xx 10^(-19)J)$

$λ = 6.12 xx 10^(-7)m$

$612 nm$ (Red light)