Question #123c3
1 Answer
Question 1: (I'm not sure what exactly the question wants to find)
Question 2:
Explanation:
I'm not quite sure what Question 1 is asking, but here's how you do Question 2:
Find the points on the curve of
So, the question has indirectly given you the gradient of the tangent by telling you what the tangent line is parallel to.
By rearranging
To find where the curve has gradient
You can see that
Let's differentiate these first, before subbing them into the formula.
Subbing these into the formula, we get:
We know that the gradient we're looking for is
When
We now have the x-coordinates of the points at which the gradient is
To find the y-coordinates, you just need to sub the points we just found back into the first function.
When
And hence we get the point
When
And hence we get the point
In short, the answer to Question 2 is