How do you use synthetic division to determine if $- 1$ $-1$ is a lower bound of $f (x) = 4 x^{3} - 2 x^{2} + 2 x - 4$ $f(x) = 4x^3-2x^2+2x-4$ ?

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How do you use synthetic division to determine if $- 1$ $-1$ is a lower bound of $f (x) = 4 x^{3} - 2 x^{2} + 2 x - 4$ $f(x) = 4x^3-2x^2+2x-4$ ?

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Answer 1 · 2017-10-06T19:14:35

$Q u o t i e n t = 4 x^{2} + 2 x + 4$ $Quotient=4x^2+2x+4$ & Remainder $= 0$ $=0$

Explanation:

$\frac{4 x^{3} - 2 x^{2} + 2 x - 4}{(x - 1)}$ $(4x^3-2x^2+2x-4)/((x-1)$ using synthetic division:
1 | 4 -2 2 -4
| 4 2 4
___
| 4 2 4 0
Quotient $= 4 x^{2} + 2 x + 4$ $=4x^2+2x+4$ & Remainder $= 0$ $=0$

Verification:
$f (1) = 4 - 2 + 2 - 4 = 0$ $f(1)=4-2+2-4=0$

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How do you use synthetic division to determine if $- 1$ $-1$ is a lower bound of $f (x) = 4 x^{3} - 2 x^{2} + 2 x - 4$ $f(x) = 4x^3-2x^2+2x-4$ ?

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How do you use synthetic division to determine if −1-1 is a lower bound of f(x)=4x3−2x2+2x−4f(x) = 4x^3-2x^2+2x-4?

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Explanation:

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How do you use synthetic division to determine if $- 1$ $-1$ is a lower bound of $f (x) = 4 x^{3} - 2 x^{2} + 2 x - 4$ $f(x) = 4x^3-2x^2+2x-4$ ?