What volume (in mL) of 9.91 M sodium chloride is required to produce 100.0 mL of a 0.398M solution?

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Answer 1 · 2017-10-06T23:13:39

#4.02 mL#

Recall that molarity and volume can be expressed in the following ratio:

#V_1M_1 = V_2M_2#

So all you have to do is plug in your values:

#V_1 * 9.91 M = 100 mL * 0.398 M#

Solve for #V_1# to get:

#V_1 = (100 mL * 0.398 M) / (9.91 M) = 4.016 mL#

With significant figures, you get a final answer of #4.02 mL#.