How do you solve #-[ 4+ 2( x + 1) ] = 3( x + 1) + 3#?

Question

1068 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-07T22:32:51

#-12/5=x#

#−[4+2(x+1)]=3(x+1)+3#

Left side:

#−[4 color(red)(+2(x+1) ]]=3(x+1)+3#

#−[4color(blue)(+2x+2)]=3(x+1)+3#

#−[color(red)4+2xcolor(red)(+2)]=3(x+1)+3#

#−[2x color(blue)(+6)]=3(x+1)+3#

#color(red)(−1[2x +6])=3(x+1)+3#

#color(blue)(−2x -6)=3(x+1)+3#

#−2x -6=3(x+1)+3#

#−2x -6=color(red)(3(x+1))+3#

#−2x -6=color(blue)(3x+3)+3#

#-2x -6=3xcolor(red)(+3+3)#

#-2x -6=3xcolor(blue)(+6)#

#-2x(color(red)(-6-6))=3xcancel(color(red)(+6-6))#

#-2xcolor(blue)(-12)=3x#

#cancelcolor(red)(-2x+2x)-12=color(red)(3x+2x)#

#-12=color(blue)(5x)#

#color(red)(-12/5)=cancelcolor(red)(5/5)x#

#color(blue)(-12/5)=color(blue)x#

#-12/5=x#

I hope this helps