Calculate the mass of Ca(NO3)2 needed to prepare 3.5 L of a 0.8 M solution?
Calculate the mass of #Ca(NO_3)_2# needed to prepare 3.5 L of a 0.8 M solution.
Calculate the mass of
1 Answer
Oct 8, 2017
459.45 g
Explanation:
Given:
concentration = 0.8 M =
volume = 3.5 L
mass = ?
molecular weight of