Question #ca344

1 Answer
Oct 8, 2017

y-5=2(x+2)y5=2(x+2)

Explanation:

Point slope form is written in the form,
y-y_1=m(x-x_1)yy1=m(xx1)
Where yy is your output, y_1y1 is a yy-value on your line, mm is your slope (given as 2 here), xx is your input, and x_1x1 is y_1y1's corresponding xx-value.

In your case, you are given all the things you need to write your equation in point-slope form. Simply plug in your mm (22), your x_1x1 (-22), and your y_1y1 (55) which should merit:

y-5=2(x+2)y5=2(x+2)

Remember that the xx-side of the equation is x-x_1xx1, so you would really end up with
"stuff"=2(x--2)stuff=2(x2)
Which simplifies to
"stuff"=2(x+2)stuff=2(x+2)