Question

How do you solve `2x + 7 \leq 19`?

Answer 1

`x <= 6`

Explanation:

First, minus the 7 from both sides of the equation and get this:
`2x <= 12`

Then divide both sides by 2 to get x on itself and get the answer:
`x <= 6`

Answer 2

`x<=6`

Explanation:

`2x+7≤19`
Subtract 7 from both sides.

`2x+7-7≤19-7`

`2x<=12`

`(2x)/(2x)<=12/(2x)`

`x<=6`

Answer 3

`x leq 6`

Explanation:

To start, pretend the`leq`symbol is really and`=`symbol, and then solve it like a normal algebra equation:

Start with `2x+7leq19`.

Replace`leq`with`=`:

`2x+7=19`

Subtract 7 from both sides to isolate `x`:

`2x=12`

Divide both sides by `2` to get `x` to be just `x`, with no coefficients or other terms:

`x=6`

Replace`=`with`leq`:

`xleq6`

(If you had multiplied or divided by a negative number, you would have had to flip the inequality sign to`geq`. But you didn't have to, so you're good.)