(sin(10°)+sin(20°)+sin(40°)+sin(50°))/(cos(10°)+cos(20°)+cos(40°)+cos(50°)) = ?

2 Answers
Dee
Oct 9, 2017

-6.405331191

Explanation:

(sin(10)+sin(20)+sin(40)+sin(50))/(cos(10)+cos(20)+cos(40)+cos(50))
You need to punch in each term in a calculator, sum up the numerator and denominator separately, then divide the two sums.

P dilip_k
Oct 9, 2017

(sin(10)+sin(20)+sin(40)+sin(50))/(cos(10)+cos(20)+cos(40)+cos(50))

=(sin(10)+sin(50)+sin(40)+sin(20))/(cos(10)+cos(50)+cos(40)+cos(20))

=(2sin(30)cos(20)+2sin(30)cos(10))/(2cos(30)cos(20)+2cos(30)cos(10))

=(2*1/2*cos(20)+2*1/2*cos(10))/(2*sqrt3/2*cos(20)+2*sqrt3/2*cos(10))

=(cos(20)+cos(10))/(sqrt3(cos(20)+cos(10)))=1/sqrt3

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