Question #7eb58

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Answer 1 · 2017-10-09T18:59:26

$0.34$ $0.34$ litres of hydrogen gas is produced.

The suggested reaction is $\to$ $rarr$

$Z n + 2 H C l \to Z n C l_{2} + H_{2} (g)$ $Zn+2HClrarrZnCl_2+H_2(g)$

Now, gram atomic mass of Zinc is $65.38 g$ $65.38g$ .

So from the equation,

$65.38 g$ $65.38g$ of $Z n$ $Zn$ produces $2 g$ $2g$ of $H_{2}$ $H_2$ .

$:.1g$ of $Zn$ produces $2/65.38g$ of $H_2$ .

Now, $1$ mole or $2g$ of $H_2$ gas occupies a volume of $22.4L$ .

$:.2/65.38g$ of $H_2$ gas occupies $rarr$

$=22.4/2xx2/65.38L$ .

$=0.34L$ . (Answer).

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