How do you solve $\frac{x^{2}-x-6}{x}=x-3$ ?

Question

922 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-10T19:03:06

$x=3$

Start by multiplying by $x$ on both sides:

$x^2-x-6=(x-3)x$

Distribute:

$x^2-x-6=x^2-3x$

Combine like terms:

$-6=-2x$

Divide both sides by $-2$

$x=3$

How do you solve \frac{x^{2}-x-6}{x}=x-3\frac{x^{2}-x-6}{x}=x-3?