Question #3d21b

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Answer 1 · 2017-10-10T19:04:31

Let's see.

You need the formula $\to$ $rarr$

$P = \frac{W}{t} = \frac{F . S}{t} = \frac{m g h}{t}$ $P=W/t=(F.S)/t=(mgh)/t$ .

Here, $m = 475 k g$ $m=475kg$ , $g = 9.8 m s^{- 2}$ $g=9.8ms^(-2)$ , $h = 10 m$ $h=10m$ & $t = 24 s$ $t=24s$ .

Substituting everything in the formula we get,

$P = \frac{475 \times 9.8 \times 10}{24} W$ $P=(475xx9.8xx10)/24W$

$:.P=1939.58W$ .

So,the power required to do the aforementioned work is $1939.58$ watts. (Answer).