Question

Question #4b3ff

Answer 1

`x=9/3`

Explanation:

Given -

`9x^2-25=0`

`9x^2=25`

`x^2=25/9`
`x=sqrt(25/9)`
`x=sqrt25/sqrt9=5/3`
`x=9/3`

Answer 2

`x=\frac{5}{3},\qquad\qquad x=-\frac{5}{3}`

Explanation:

This is the standard form of a quadratic equation, which we can find the roots of by using the quadratic formula.

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Rewriting the equation:

`9x^2+0x-25=0`

Our values to plug into the formula are:

• `a=9`

• `b=0`

• `c=-25`

The formula is:

`x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}`

Plugging in for the variables:

`x=\frac{0\pm\sqrt{0^2-4(9)(-25)}}{2(9)}`

`x=\frac{0\pm\sqrt{0+900}}{18}`

`x=\frac{0\pm\sqrt{900}}{18}`

`x=\frac{0\pm 30}{18}`

`x=\frac{15}{18},\qquad\qquad x=-\frac{30}{18}`

`\therefore x=\frac{5}{3},\qquad\qquad x=-\frac{5}{3}`