Question

Question #b0422

Answer 1

The required equilibrium constant is `1/(4sqrt(3))`.

Explanation:

Given, `H_2+I_2rightleftharpoons2HI`

Equilibrium constant for the reaction, `K=48`.

So, if the reverse reaction is considered `rarr`

`2HIrightleftharpoonsH_2+I_2`

Then the equilibrium constant `(K_r)` for this reaction would also be reversed.

So, `K_r=1/K=1/48`.

Now, let us consider that all the coefficients of the entities of the previous reaction are multiplied by a common multiplier, `1/2`.

So, the new reaction will be `rarr`

`HIrightleftharpoons1/2H_2+1/2I_2`

so, the new equilibrium constant for the reaction `(K_(eq))` is `rarr`

`K_(eq)=K_r^(1/2)`

`:.K_(eq)=(1/48)^(1/2)`

`:.K_(eq)=1/(4sqrt(3))`. (Answer).

Hope it Helps:)