How do you solve $-8 + 4a -12 > 2a +10$ ?

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Answer 1 · 2017-10-11T18:24:14

Combine like terms and isolate the variable. $a>15$

$-8+4a-12>2a+10 -> 4a-20>2a+10$

Add 20 to both sides and subtract 2a from both sides.

$4a-20+20>2a+10+20 -> 4a>2a+30 -> 4a-2a > 2a-2a+30 -> 2a>30$

Divide both sides by 2.

$2a/2 >30/2 -> a>15$

How do you solve -8 + 4a -12 > 2a +10-8 + 4a -12 > 2a +10?