How much heat in kcal does #"26.4 g"# of diethyl ether absorb if it was heated from #12.7^@ "C"# to #30.5^@ "C"#? The specific heat capacity is #"0.895 cal/g"^@ "C"# in this temperature range.

1 Answer
Gaya3 · Truong-Son N.
Oct 12, 2017

#q = "0.421 kcal"#

Explanation:

#q=mC_P∆T#

Here,

  • #m="26.4 g"#, the mass of diethyl ether
  • #C_P= "0.895 cal"/("g"cdot^@"C")#, its specific heat capacity
  • #∆T=30.5^@ "C" - 12.7^@ "C" = 17.8^@ "C"#, its change in temperature
  • #q=?#, its heat flow

So,

#q=26.4cancel(g) times 0.895"cal"/cancel(g^@C)times17.8^@cancelC#

#q="420.6 cal" =# #ul("0.421 kcal")#

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