How do you solve $\frac{3}{4} x - 4 = 7 + \frac{1}{2} x$ $\frac{3}{4}x-4=7+1/2x$ ?

Question

1092 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-12T06:33:50

By arranging the equation

Add 4 to each side.

$\frac{3}{4} x - 4 + 4 = 7 + \frac{1}{2} x + 4$ $3/4 x - 4 + 4=7+ 1/2 x +4$

$\frac{3}{4} x = \frac{1}{2} x + 11$ $3/4 x = 1/2 x + 11$

$\frac{3}{4} x - \frac{1}{2} x = 11$ $3/4 x - 1/2 x = 11$

$\frac{3}{4} x - \frac{2}{4} x = 11$ $3/4 x - 2/4 x = 11$

$\frac{1}{4} x = 11$ $1/4 x = 11$

$x = 11 \times 4 = 44$ $x = 11times4 = 44$

This is your answer. $x = 44$ $x=44$ .

How do you solve 34x−4=7+12x\frac{3}{4}x-4=7+1/2x?