Question

How do you find the limit `lim 5^(x^2-2x+1)` as `x->3`?

Answer 1

First thing to do is...

Explanation:

For these sorts of limit problems, the first thing to try is always just to substitute the value that x is approaching, and see what the function evaluates to. If it's defined and has a value at that point, then your work is done.

Here, if `x=3`, then `x^2-2x+1 = 9 - 6 + 1 = 4`

So you have `5^4 = 625`

GOOD LUCK