Question #f956d

2 Answers
Oct 12, 2017

No.

Explanation:

#2^2=4# and #3^2 = 9# but neither #9+4=13# nor #9-4=5# is a perfect square.

Oct 12, 2017

Let's have a look.

Explanation:

Actually matters.

Let us take few cases:#rarr#

(1). Square of even numbers.

#(2n)^2+(2n+2)^2#

#=5n^2+4n+4#.

This is not a perfect square.

Example #rarr#

#2^2+4^2#

#=4+16#

#=20#

#=4sqrt(5)#.

(2). Square of odd numbers.

#(2n+1)^2+(2n+3)^2#

#=8n^2+16n+10#.

This is not a perfect square.

Example #rarr#

#1^2+3^2#

#=1+9#

#=10#

(3). Square of even & odd numbers.

#(2n)^2+(2n+1)^2#

#=8n^2+4n+1#

This is not a perfect square.

Example #rarr#

#1^2+2^2#

#=1+4#

#=5#

But there are certain cases when, the third condition gets satisfied.

In certain cases, sum of squares of an even & an odd number turns to be a perfect square.

For example #rarr#

#3^2+4^2#

#=9+16#

#=25#

#=5^2#.

So, it does matter.

Hope it Helps:)