How do you solve #-19< \frac { x } { 12}#?

1 Answer
EET-AP
Oct 13, 2017

#-228 < x#
On a number line you would have a large negative line drawn back towards #-228#, but with a #circ# at #-228# because #x# is greater than it. On the #+# side the line would go to infinity.

Explanation:

#-19 < x/12#

#-19xx12 < (x/cancel12)xxcancel12#

#-228 < x#

Related questions
Impact of this question
845 views around the world
You can reuse this answer
Creative Commons License