Question

`x^2-10x+?=(?-?)^2`

Answer 1

`x^2-10x+25=(x-5)^2`

Explanation:

We want to add a number on the left so we get a perfect square on the right. A quick way to do this is to add `(b/2)^2`, in this case that is:

`(-10/2)^2=25`

So:

`x^2-10x+25=(?-?)^2`

Factoring we get:

`x^2-10x+25=(x-5)^2`