How do you find the domain and range of #sqrt(x - 1)#?

1 Answer
Samuel A.
Oct 13, 2017

You can get the domain by working with the assumption that the function's domain lie in a set of all real numbers, that is #(x - 1)# must be greater than or equal to zero.

Explanation:

If #(x - 1)# must be greater than #0# then #x >= 1# must be true for all values of #x#.

Therefore the domain is #x >= 1#

The range is suppose to be the set of all values of the function that lies within the domain.
The least member of the domain set above is #x = 1# and the value of the function at this value of #x# is #√1# which is #1#.
Therefore the range is #{1, ...}#

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