How do you write the standard form of the hyperbola #-x^2+y^2-18x-14y-132=0#?

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Answer 1 · 2017-10-13T18:18:50

Standard form of the hyperbola equation :
#(y-7)^2/100-(x+9)^2/100=1#.

The standard form of a hyperbola with centre, #(alpha,beta)# is #rarr#

#(y-beta)^2/b-(x-alpha)^2/a=1#

Therefore, the given expression can be arranged as #rarr#

#-(x^2+18x+81)+(y^2-14y+49)=(132-81+49)#

#:.(x+9^2)-(y-7)^2=-100#

#:.((x+9)^2/-100)-((y-7)^2/-100)=1#

#:.(y-7)^2/100-(x+9)^2/100=1#. (Answer).

Hope it Helps:)