Question

How do you solve `\frac { 2 k + 5} { 5} + 9= - ( k - 3)`?

Answer 1

`k=-5`

Refer to the explanation for the process.

Explanation:

Solve:

`(2k+5)/5+9=-(k-3)`

Expand the right side.

`(2k+5)/5+9=-k+3`

Subtract `9` from both sides.

`(2k+5)/5=-k+3-9`

Simplify.

`(2k+5)/5=-k-6`

Multiply both sides by `5`.

`2k+5=5(-k-6)`

Simplify.

`2k+5=-5k-30`

Subtract `5` from both sides.

`2k=-5k-30-5`

Simplify.

`2k=-5k-35`

Add `5k` to both sides.

`2k+5k=-35`

Simplify.

`7k=-35`

Divide both sides by `7`.j

`k=-35/7`

Simplify.

`k=-5`

Answer 2

`k=`-5

Explanation:

Taking L C M and removing bracket in R H S,
`(2k+5+45)/5=-k+3`

`2k+50=-5k+15` Cross multiplying and simplifying LHS,

`2k+5k=-50+15` Bringing k terms to LHS and constants to RHS.

`7k=-35`

`k=(-35)/7=`-5