Question #10e39

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Answer 1 · 2017-10-15T04:23:05

#y=-1/2x+3#

First, find the midpoint of the line segment.

#((8+4)/2 , (4+(-4))/2)#
#=(6,0)#

Then, find the gradient of the line segment #color(purple)m#.
#(y_2-y_1)/(x_2-x_1)#

#=(-4-4)/(4-8)#

#=(-8)/-4#

#=2#

So the gradient of the bisector is #(-1)/color(purple)m = =(-1)/2#

Using the Cartesian equation #rArr y-y_1=m(x-x_1)#

#y-0=-1/2(x-6)#
#y=-1/2x+3#