How do you evaluate $(x^{2} + 4 x + 3) (2 x^{2} - 9 x + 7)$ $(x ^ { 2} + 4x + 3) ( 2x ^ { 2} - 9x + 7)$ ?

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How do you evaluate $(x^{2} + 4 x + 3) (2 x^{2} - 9 x + 7)$ $(x ^ { 2} + 4x + 3) ( 2x ^ { 2} - 9x + 7)$ ?

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Answer 1 · 2017-10-15T12:34:17

$2 x^{4} - x^{3} - 23 x^{2} + x + 21$ $2x^4-x^3-23x^2+x+21$

Explanation:

The idea behind multiply any two polynomials is to multiply each term in one polynomial with every term in the other polynomial. Let's see this in action:

$(x^{2} + 4 x + 3) \cdot (2 x^{2} - 9 x + 7)$ $(x^2+4x+3)*(2x^2-9x+7)$

$= x^{2} \cdot (2 x^{2} - 9 x + 7) + 4 x \cdot (2 x^{2} - 9 x + 7) + 3 \cdot (2 x^{2} - 9 x + 7)$ $=x^2*(2x^2-9x+7)+4x*(2x^2-9x+7)+3*(2x^2-9x+7)$

$= 2 x^{4} - 9 x^{3} + 7 x^{2} + 8 x^{3} - 36 x^{2} + 28 x + 6 x^{2} - 27 x + 21$ $=2x^4-9x^3+7x^2+8x^3-36x^2+28x+6x^2-27x+21$

$= 2 x^{4} - x^{3} - 23 x^{2} + x + 21$ $=2x^4-x^3-23x^2+x+21$

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How do you evaluate $(x^{2} + 4 x + 3) (2 x^{2} - 9 x + 7)$ $(x ^ { 2} + 4x + 3) ( 2x ^ { 2} - 9x + 7)$ ?

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Science

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How do you evaluate (x2+4x+3)(2x2−9x+7)(x ^ { 2} + 4x + 3) ( 2x ^ { 2} - 9x + 7)?

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Explanation:

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How do you evaluate $(x^{2} + 4 x + 3) (2 x^{2} - 9 x + 7)$ $(x ^ { 2} + 4x + 3) ( 2x ^ { 2} - 9x + 7)$ ?