How do you solve #\frac { 3x } { 6} - \frac { 4x + 6} { 5} = 5#?

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Answer 1 · 2017-10-16T03:55:32

#x=-62/3#

Make the denominators the same by multiplying them with each other.

#(3x(5))/(6xx5) - (6(4x+6))/(6xx5) = 5#

#(15x-24x-36)/30=5#

Multiply both equations by #30# to remove it.

#15x-24x-36=150#

#-9x=186#

#:.x=-62/3#

Answer 2 · 2017-10-16T04:01:48

x = -20(2/3)

Taking L CM for 5, 6 as 30,
#((5*3x)-(6*(4x+6)))/30=5#

#15x-24x-36 = 150#
#-9x = 150+36 = 186#
#x = -20(2/3)#