How do you solve \frac { 8} { x } + \frac { 2} { x - 4} = \frac { x - 2} { x - 4}8x+2x−4=x−2x−4?

1 Answer
EET-AP
Oct 16, 2017

x=8x=8

Explanation:

8/x+2/(x-4)=(x-2)/(x-4)8x+2x−4=x−2x−4

8/x=-2/(x-4)+(x-2)/(x-4)=(-2+x-2)/(x-4)=(x-4)/(x-4)=18x=−2x−4+x−2x−4=−2+x−2x−4=x−4x−4=1

8/x=18x=1

8/cancelx(cancelx)=1(x)

8=x

To check, change all x to 8:

8/8+2/(8-4)=(8-2)/(8-4)

1+1/2=6/4

1 1/2=1 1/2

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