Question #29fd4

1 Answer
Oct 16, 2017

dydx=23csc2(x3) where csc is cosec.

Explanation:

y=2cot(x3)

Differentiate both sides

ddx(y)=ddx(2cot(x3))

Apply the chain rule.

As we know the derivative of cotx is csc2x

dydx=2csc2(x3)ddx(x3)

dydx=2csc2(x3)13

dydx=23csc2(x3)