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Question #c6f62

1 Answer

Oct 16, 2017

$- 2 < r \leq 0$ $-2< r <=0$

Explanation:

Split up the inequalities into two parts.
$9 + 7 r > r - 3$ $9+7r>r-3$ and $r - 3 \geq 7 r + 3$ $r-3>=7r+3$
Solve them.

$9 + 7 r > r - 3$ $9+7r>r-3$
$6 r > - 12$ $6r> -12$
$r > - 2$ $r> -2$

$r - 3 \geq 7 r + 3$ $r-3>=7r+3$
$0 \geq 6 r$ $0>=6r$
$0 \geq r$ $0>=r$

Since $r$ $r$ has to be more than $- 2$ $-2$ and less than $0$ $0$ , we can rewrite the inequality as $- 2 < r \leq 0$ $-2< r <=0$

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