Question #e39a0

1 Answer
Subha
Oct 18, 2017

-2*{x-(-1)}^2+8−2⋅{x−(−1)}2+8

Explanation:

-2*(x+3)(x-1)−2⋅(x+3)(x−1)
= -2*(x^2+3*x-x-3)=−2⋅(x2+3⋅x−x−3)
= -2*(x^2+2*x-3)=−2⋅(x2+2⋅x−3)
= -2*(x^2+2*x+1) +8=−2⋅(x2+2⋅x+1)+8
= -2*(x+1)^2 +8=−2⋅(x+1)2+8
= -2*{x-(-1)}^2 +8=−2⋅{x−(−1)}2+8
It is the vertex form of the equation.

Note that a equation is said to be in vertex form if it is in the form a*(x-h)^2 +ka⋅(x−h)2+k where x is variable & others are constant.

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