How do you solve $\frac{2}{3} t + \frac{1}{5} = 3$ $\frac { 2} { 3} t + \frac { 1} { 5} = 3$ ?

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Answer 1 · 2017-10-19T04:17:03

$t = \frac{21}{5}$ $t=21/5$ or $4.2$ $4.2$

Subtract both sides of the equation by $\frac{1}{5}$ $1/5$ so you can solve for $t$ $t$ .

$\frac{2}{3} t = 3 - \frac{1}{5}$ $2/3t=3-1/5$

$\frac{2}{3} t = \frac{14}{5}$ $2/3t=14/5$

Multiply both sides by $3$ $3$ so you get rid of it as a denominator.

$2 t = \frac{42}{5}$ $2t=42/5$

Solve for $t$ $t$ by dividing both sides of the equation by $2$ $2$ .

$:.t=21/5$ or $4.2$

How do you solve \frac { 2} { 3} t + \frac { 1} { 5} = 323t+15=3\frac { 2} { 3} t + \frac { 1} { 5} = 3?