Question

A particle travels 10m in 5sec and 10m in 5sec and 10m in 3sec assuming constant acceleration what is the distance travelled in next 2sec? Ans:8.3m

Answer 1

The distance traveled is 8.125m

Explanation:

`u1 = 10/5=2` m/s ; `t1=8 s`

`v1= 20/8=2.5`m/s

`a= (v1-u1)/t=(2.5-2)/8=0.0625` m/`s^2`

`u2=v1=2.5`m/s ; `t2=10s`

`s=u2*t2+(0.5*at2^2) = 2.5*10+(0.5*0.0625*10*10)`
Therefore, `s=28.125` m

The distance traveled `=28.125-20=8.125` m