A car slows down uniformly from a speed of 21.0 m/s to rest in 6.00 sec. How far did it travel in that time?

1 Answer
Junaid Mirza
Oct 20, 2017

"63.0 m"63.0 m

Explanation:

text(Acceleration of car) = (v - u) / t = ("0 ms"^-1 - "21.0 ms"^-1) / ("6.00 s") = -"3.50 ms"^-2Acceleration of car=v−ut=0 ms−1−21.0 ms−16.00 s=−3.50 ms−2

"S" = ("v"^2 - "u"^2) / ("2a")S=v2−u22a

color(white)("S") = [("0 ms"^-1)^2 - ("21.0 ms"^-1)^2] / (2 × -"3.50 ms"^-2)S=(0 ms−1)2−(21.0 ms−1)22×−3.50 ms−2

color(white)("S") = 63.0\ "m"

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