0.2(10-5c) = 5c - 16
In order to solve this, we need to isolate c, which means get it by itself. So, let's start by getting rid of those parentheses and distributing that 0.2.
0.2(10-5c) = 5c - 16
2-1*c = 5c - 16
Now let's get all the color(orange)(const ants) (numbers) on one side
subtract 2 on both sides
-c = 5c color(orange)(- 16 - 2)
Now let's get the color(blue)(variab l es_ on one side
subtract 5c from both sides
color(blue)(-c - 5c) = -16 - 2
Let's combine everything and see what we've got
-6c = -18
We're almost there, but c still isn't by itself. We need to get rid of that pesky -6
divide by -6 on both sides
c = (-18)/-6
c = 3
. . . . . . . . . . . . . . . . . . . . . . . .
To check our work, let's plug in 3 for c and make sure both sides are equal:
0.2(10-5color(red)(c)) = 5color(red)(c) - 16
0.2(10-(5*3)) = (5*3) - 16
0.2(10-15) = 15 - 16
0.2(-5) = -1
color(green)(-1 = -1)
We were right! Great job
