What is the equation of a line, in the form #ax+by+c=0#, with gradient -2 through the point (4, -6)?

1 Answer
Oct 20, 2017

First, we should know that slope of linear equation is #m=(y1-y2)/(x1-x2)# and we can form the equation by this formula.

In this case, we have gradient (slope)= #-2# and the point (4, -6). We can just simply sub the things we know into the above equation.

So, the equation will be:
#-2= (y-(-6))/(x-4)#
#-2(x-4)=y+6#
#-2x+8=y+6#

And we can change it in the form #ax+by+c=0#, which is
#-2x-y+2=0#