Represent √3+i in polar form?

2 Answers
Oct 21, 2017

See Explanation

Explanation:

Tony BTony B

Oct 21, 2017

sqrt(3) + i = 2(cos(pi/6) + isin(pi/6))

Explanation:

Let sqrt(3) + i = z

Modulus of z:

|z| = sqrt(sqrt(3)^2 + 1^2) = sqrt(4) = 2 = r

Argument of z:

arctan(1/sqrt(3)) = pi/6 = theta

z = r(cos(theta) + isin(theta)) = 2(cos(pi/6) + isin(pi/6))