Question

What is the equation for the function that passes through the points `(1, 3/2) and (3/2, 2)`?

Answer 1

Let's have a look.

Explanation:

Let the function or more specifically, the line be a function of both `x` & `y`.

Now, equation of a straight line passing through the points `(x_1,y_1)` & `(x_2,y_2)` be `rarr`

`color(red)(y-y_1=m(x-x_1))`.

where, `m` is the slope of the line.

`color(red)(m=(y_2-y_1)/(x_2-x_1))`

Now, substituting the points given in the above equations, we get `rarr`

`color(red)(y-3/2=((2-3/2)/(3/2-1))xx(x-1))`.

Now, simplify the equation to get the desired one.

Hope it Helps:)