How do you evaluate $5 (14 - 39 \div 3) + 4 \cdot \frac{1}{4}$ $5(14-39div3)+4*1/4$ ?

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Answer 1 · 2017-10-22T21:09:27

$9 (\frac{1}{4})$ $9(1/4)$

$5 (14 - (\frac{39}{3})) + 4 (\frac{1}{4})$ $5 ( 14 - (39/3) ) + 4(1/4)$

$= 5 (14 - 13) + 4 + (\frac{1}{4})$ $= 5 (14-13) + 4 + (1/4)$

$= 5 + 4 + (\frac{1}{4}) = 9 + (\frac{1}{4}) = 9 (\frac{1}{4})$ $= 5 + 4 + (1/4) = 9 + (1/4) = 9(1/4)$

Answer 2 · 2017-10-22T21:33:36

$5 (14 - \frac{39}{3}) + 4 \cdot \frac{1}{4} = 6$ $5(14-39/3)+4*1/4=6$

We need to evaluate what is inside the parenthesis first:

$5 (14 - \frac{39}{3}) + 4 \cdot \frac{1}{4} = 5 (14 - 13) + (4 \cdot \frac{1}{4}) = 5 (1) + 1 = 6$ $5(14-39/3)+4*1/4=5(14-13)+(4*1/4)=5(1)+1=6$

And then complete the addition.

How do you evaluate 5(14−39÷3)+4⋅145(14-39div3)+4*1/4?