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1 Answer
reudhreghs
Oct 22, 2017

#1.1" micromoles"#

Explanation:

You should consider the equation

#n = cv#

where #n# is the number of moles (or micromoles), #c# is the concentration and #v# is the volume.

The question gives us a volume of #0.35L# or #0.35"dm"^3# (which are the same) and a concentration of #3.1xx10^-6M# or #3.1xx10^-6"moldm"^-3#.

Therefore,

#n = 0.35"dm"^3 xx 3.1 xx 10^-6"moldm"^-3 = 1.085 xx 10^-6"mol"#

So we know there are #1.085 xx 10^-6"mol Hg"_2"Cl"_2# in the solution, which is about #1.1# micromoles of mercury(I) chloride, since there are #10^6"micromol"#s in a mol.

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