How do you find the domain and range of y=x^2 - 5y=x25?

1 Answer
Oct 24, 2017

-oo < x < oo<x<
y >= -5y5

Explanation:

The domain is the set of xx values a function can take to give a real yy value, which in the function y = x^2 -5y=x25 is simply any xx value. For instance, when x=-6x=6 then y = 36-5 = 31y=365=31. Similarly, when x=1000x=1000, then y=1000000-5=999995y=10000005=999995.

Therefore, -oo < x < oo, x in RR.

However, for x in RR, x^2 >= 0. In other words, a square number is always positive (greater than 0), so a square number minus five must be always greater than minus five. So,

x^2 >= 0

:.

x^2 - 5 >= -5

:.

y >= -5

This is the range of the function, which is defined as the set of y values that can be taken by the function. You'll never find a (real) solution for anything less than y = -5, for which x = 0.