How many ways can 4 students be arranged in a row?

1 Answer
Oct 24, 2017

4!=4×3×2×1=24 possibilities

Explanation:

Let's say they're going to be sat on chairs, numbered 1,2,3,4.

To start with, the students are stood off to the side and you have to sit them on the chairs.

For chair 1, you have 4 students stood off to the side, so there are 4 possibilities for chair 1.

No matter which student you choose, you will sit a student on the chair and have 3 students left standing. This means that for chair 2, you have 3 possibilities.

Now again, no matter who you choose, you have 2 students left standing, so there are 2 possibilities for chair 3.

Now you'll sit the last one down on the last chair - there's only 1 possibility for the last chair.

In probability, when you have certain numbers of possibilities for a certain number of events, you multiply the numbers of possibilities, so you have

4×3×2×1=24 possibilities overall.

This is also known as 4-factorial, or 4!.