How do you solve $- 7 n - 2 (2 - 6 n) = 2 (1 + 2 n)$ $-7n - 2( 2- 6n ) = 2( 1+ 2n )$ ?

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Answer 1 · 2017-10-25T03:21:28

$n = 6$ $n=6$

First, distribute the parenthesis.
$- 7 n - 2 (2 - 6 n) = 2 (1 + 2 n)$ $-7n-2(2-6n)=2(1+2n)$
$- 7 n - 4 + 12 n = 2 + 4 n$ $-7n-4+12n=2+4n$

Then we want to isolate all the terms with the variable $n$ $n$ .
$- 7 n + 12 n - 4 n = 2 + 4$ $-7n+12n-4n=2+4$

Then we combine-like terms.
$n = 6$ $n=6$

How do you solve −7n−2(2−6n)=2(1+2n)-7n - 2( 2- 6n ) = 2( 1+ 2n )?